Ok,
I've got a serious question for the smart people here on the Hide...
Let's say that given a 2 story house, there are 2 bathrooms/toliets on the 1st floor & 2 bathrooms/toliets on the 2nd floor. Let's also say that all of the toilets are exactly the same (aside from location/elevation) and that the sewer goes out in the basement directly beneath the 1st floor. So all toilets are the same make & model and since this is America in this scenario... let's call one of the constants that all of the toilets are rated at 1.6 GPF.
So here's my question, and yes I'm being serious here (hence I why I said no weirdos and trying to recruit educated & experienced professionals here). As a layperson, I may be using the wrong terminology but would the 2 toilets on the 2nd floor have the equivalent of a "mechanical advantage" to that of the 2 toilets on the 1st floor of the house?
Here's why I ask- I'd have to believe that a higher elevation from the sewer throughput would be able to take advantage of gravitational pull but, as we all learned in school, gravitational pull is constant (9.8 m/s^2 if I remember my schooling from lifetimes ago). BUT- there's also the forces that allow a siphon to work that is aiding into the gravitational constant. It's been a VERY long time since I took HS chemistry but I feel like there was something about weak ionic bonds that factored into that science.
In this scenario, most of the controllables are controlled- the flow rate of the flush (1.6 GPF) and with the models being identical & the water trap bend being the same on both the 1st and 2nd floor, is there a "mechanical/hydraulic" advantage to the toilet on the 2nd floor or does the water trap bend act as a regulator?
If it isn't mathematically significant (assuming that elevation poses a quantifiable, albeit minor, difference) at what elevation would the higher toilet be required to be at from the out pipe to take advantage of it's elevation given that all things are otherwise equal?
Thanks in advance.
-LD
I've got a serious question for the smart people here on the Hide...
Let's say that given a 2 story house, there are 2 bathrooms/toliets on the 1st floor & 2 bathrooms/toliets on the 2nd floor. Let's also say that all of the toilets are exactly the same (aside from location/elevation) and that the sewer goes out in the basement directly beneath the 1st floor. So all toilets are the same make & model and since this is America in this scenario... let's call one of the constants that all of the toilets are rated at 1.6 GPF.
So here's my question, and yes I'm being serious here (hence I why I said no weirdos and trying to recruit educated & experienced professionals here). As a layperson, I may be using the wrong terminology but would the 2 toilets on the 2nd floor have the equivalent of a "mechanical advantage" to that of the 2 toilets on the 1st floor of the house?
Here's why I ask- I'd have to believe that a higher elevation from the sewer throughput would be able to take advantage of gravitational pull but, as we all learned in school, gravitational pull is constant (9.8 m/s^2 if I remember my schooling from lifetimes ago). BUT- there's also the forces that allow a siphon to work that is aiding into the gravitational constant. It's been a VERY long time since I took HS chemistry but I feel like there was something about weak ionic bonds that factored into that science.
In this scenario, most of the controllables are controlled- the flow rate of the flush (1.6 GPF) and with the models being identical & the water trap bend being the same on both the 1st and 2nd floor, is there a "mechanical/hydraulic" advantage to the toilet on the 2nd floor or does the water trap bend act as a regulator?
If it isn't mathematically significant (assuming that elevation poses a quantifiable, albeit minor, difference) at what elevation would the higher toilet be required to be at from the out pipe to take advantage of it's elevation given that all things are otherwise equal?
Thanks in advance.
-LD
