Re: 1/2 MOA at 1760 yards doable??
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Jim the Plumber</div><div class="ubbcode-body">1 mile with my AR 50. I also shoot quite a bit at 1245 yards.
Target board is 36"x48".
This is a group I shot at 950 last week with my 6.5Lapua . Two outside shots fired first to correct for wind, then 5 for effect. They went 5.5". </div></div>
Yes - you have pictorial proof that when you remove wide shots from a shot grouping, the group becomes smaller, regardless of the distance it was shot at or the rifle used to do the shooting.
If one were to get their SD down into single digits then use a machine rested (bolted to a concrete pillar) projectile launcher one would find that as the amount of atmosphere between the rifle and the target directly effects the ability to fire the projectiles into the same spot.
My point is, once you remove the shooter and the load from the equation, what do you have left? What does your original question really set out to prove or dis-prove?
Please do not take this as criticism Jim. My posts like this are purely to promote further thought on a line of thinking someone is following, like you in this case. What are you trying to prove? In the quest for that proof, how many variables can you eliminate and how will you eliminate them?
Back in the late 90's Dr. Taylor and others published a series of articles in Precision Shooting that involved his "Balanced Flight" theory, the bigger cases, the .408 bore diameter, heavy rifles, and lathe-turned projectiles. We are 10+ years (and many lawsuits) post that work yet people are still asking the same questions. Did they really answer anything? Did they really invent something or change the way bullets fly or create a theory and methodology that can be scaled up and scaled down in an order to improve accuracy and repeatability in existing small arms and artillery?
