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BC Method of Doping Wind - Brackets?

kmckinnon

Sergeant of the Hide
Full Member
Minuteman
Aug 20, 2019
208
445
I'm reading Frank Galli's book where in it's described using the first number of your bullets BC to determine the MPH of your rifle. The example, a 308 using a bullet with a BC of 485 to 496 is a "4 MPH rifle". One may then work in multiples of 4 mph (and not the traditional/usual 10 mph) to dope wind. I get this.

But I got confused when in a later it is said "I just need to know my brackets then do simple addition in my head." The example at 600 yards, with a 4 mph wind is the first bracket, so that means a .6 Mil hold. Makes sense to me. But it goes on to say "If the wind is 12 mph, I am in bracket 2, so the wind hold is 1.2 Mils." While 2 x .6 Mil = 1.2 Mils, I don't get 12 mph being in bracket 2. If I have a 4 mph rifle wouldn't a 12 mph wind put me in bracket 3 (12/4 = 3) ? And that's followed by an example 18 mph wind being bracket 3 with a 1.8 Mil hold (3 x .6 = 1.8). Again, I get how I get to 1.8 but if I'm using a 4 mph multiple wouldn't 18 mph put me in bracket 4 (18/4 = 4 and change).

The last example provided describes engaging an 8 mph wind with a 308 rifle at a 400 yard target and the WTF suggested dial of .8 Mils for the first shot. 400 = .4 Mils so using a 4 MPH rifle I'd need 8/4 = 2 giving me 2 x .4 Mils = .8 Mils. Is an 8 mph wind putting me in bracket 2?

I'm working with a 308/4 MPH rifle but not understanding brackets, or at least the size of brackets. If an 8 mph wind gets me bracket 2, how does a 12 mph wind get me bracket 2? And an 18 mph wind get me bracket 3?

Thanks in advance for helping this total newb!
 
Now if the example using a 12 mph wind putting me in bracket 2 was using a 6.5 CM with irs bullets BC in the 5xx range then I could see 12 mph putting me in bracket 2 (12/5 = 2 and change) and an 18 mph wind getting me to bracket 3 (18/5 = 3 and change).

Perhaps my confusion comes from thinking the examples were for a 308/4mph rifle used in some examples while this particular example was for a 6.5CM/5mph rifle?

This discussion and examples are in Precision Rifle Marksmanship: The Fundamentals, pages 178-179.
 
I read this last night. I reread it two more times because there is a disconnect somewhere. I assumed it was with me, but for the life of me I can't put all the pieces together.
 
Can you post a screenshot or link to this small part of the book so we can understand this? I googled and tried AI it but didn't come back with a satisfactory explanation. I'll say that it's common to have a wind formula setup where your correction = speed*yardline / coefficient, and I have seen and used those in the past.

I prefer the practice of building a table with a quality ballistics calculator and then going off of that. You just start with much more accuracy. You can also build a custom formula for your particular setup if you are slightly handy with Excel. I'll even make an Excel file for you if you like, just give me your bullet info.