Can we talk about wind for a second? Not in terms of effect on windage, but effects on elevation. Specifically would like to hear thoughts on the effects of headwind on a bullet(and conversely tailwind) and the effects of aerodynamic jump(and if the opposite exists?)
What’s prompting this? This past weekend I shot my .223 AR out to 1,040 yards in Colorado. Wind was 16-46 MPH, hovering at 22-23 mph, and wind was 9-1 o clock. It was my first day shooting in high wind conditions. We made hits successfully and repeatable, but I noticed something when I got home to review everything.
It appeared that the amount of wind was effecting the vertical path of the bullet. I have numbers below to discuss so we have something tangible, but I want to run this past you to make sure I’m adjusting correctly in the future, to create a rule for a rifle/find patterns. I have heard Todd Hodnett call rifles “10mph guns”, when talking about aerodynamic jump, so I’m hoping to understand that better. The below is examples/my thoughts on what’s going on, would like to confirm and pick brains please!
DA of 5850, using 75gr BTHP, AB on Iphone.
Effects of headwind/opposite of aerodynamic jump?
Drop at 1,040 yards in Mils then inches
No wind: 12.9 mils. 483 inches
12 o clock wind, 22.5 mph: 13.2. 494 inches
11 o clock wind, 22.5 mph: 13.3(conditions for the day, making hits) 498 inches
10 o clock wind, 22.5 mph: 13.3. 498 inches
9 o clock wind, 22.5 mph: 13.2. 494 inches
The interesting thing here is the 9 o clock wind. Exact opposite jump of the 3 o clock wind, but in drag.
To me, this looks like the exact opposite of aerodynamic jump, it looks like drag. Every 7 mph is .1 mil of drag if it’s coming from the left, and every 7mph is .1 mil of jump if coming from the right. And, less drag/jump at ¾ ½ value winds.
Effects of aerodynamic jump/how many MPH is .1 mil
No wind: 12.9 mils. 483 inches
3 o clock wind, 22.5 mph: 12.6. 471 inches
2 o clock wind, 22.5 mph: 12.8. 478 inches
1 o clock wind, 22.5 mph: 13. 486 inches
To me, it looks like I have a 7mph gun, meaning full value wind at 3 o clock, every 7mph of wind is .1 mil. 22mph, .3 mil jump. I believe you are able to apply aerodynamic jump to the “value” system for wind as well, shown by the numbers. 2 o clock was less than the 3 value, more than the 1 value. 1 o clock is basically null, and drag from wind comes into play.
Would it make sense to add aero jump to part of a wind call? Dial elevation, make wind call, make calculation for aero jump/aero drag and dial that in, then hold wind?
What’s prompting this? This past weekend I shot my .223 AR out to 1,040 yards in Colorado. Wind was 16-46 MPH, hovering at 22-23 mph, and wind was 9-1 o clock. It was my first day shooting in high wind conditions. We made hits successfully and repeatable, but I noticed something when I got home to review everything.
It appeared that the amount of wind was effecting the vertical path of the bullet. I have numbers below to discuss so we have something tangible, but I want to run this past you to make sure I’m adjusting correctly in the future, to create a rule for a rifle/find patterns. I have heard Todd Hodnett call rifles “10mph guns”, when talking about aerodynamic jump, so I’m hoping to understand that better. The below is examples/my thoughts on what’s going on, would like to confirm and pick brains please!
DA of 5850, using 75gr BTHP, AB on Iphone.
Effects of headwind/opposite of aerodynamic jump?
Drop at 1,040 yards in Mils then inches
No wind: 12.9 mils. 483 inches
12 o clock wind, 22.5 mph: 13.2. 494 inches
11 o clock wind, 22.5 mph: 13.3(conditions for the day, making hits) 498 inches
10 o clock wind, 22.5 mph: 13.3. 498 inches
9 o clock wind, 22.5 mph: 13.2. 494 inches
The interesting thing here is the 9 o clock wind. Exact opposite jump of the 3 o clock wind, but in drag.
To me, this looks like the exact opposite of aerodynamic jump, it looks like drag. Every 7 mph is .1 mil of drag if it’s coming from the left, and every 7mph is .1 mil of jump if coming from the right. And, less drag/jump at ¾ ½ value winds.
Effects of aerodynamic jump/how many MPH is .1 mil
No wind: 12.9 mils. 483 inches
3 o clock wind, 22.5 mph: 12.6. 471 inches
2 o clock wind, 22.5 mph: 12.8. 478 inches
1 o clock wind, 22.5 mph: 13. 486 inches
To me, it looks like I have a 7mph gun, meaning full value wind at 3 o clock, every 7mph of wind is .1 mil. 22mph, .3 mil jump. I believe you are able to apply aerodynamic jump to the “value” system for wind as well, shown by the numbers. 2 o clock was less than the 3 value, more than the 1 value. 1 o clock is basically null, and drag from wind comes into play.
Would it make sense to add aero jump to part of a wind call? Dial elevation, make wind call, make calculation for aero jump/aero drag and dial that in, then hold wind?