From 100yd zero Holdover at 25yds measures 1.50 inches but it takes 2.0 MILS. Why????

[charliebrown1999]

My Browning X-Bolt Max Varmint/Target is zeroed at 100yds. To hit zero at 25yds I want to holdover because I want to retain the 100yd zero for shooting 625yds at Pala shooting range. Upon firing the rifle at 25yds indoors the point of impact is 1.50 inches low as measured by calipers. So knowing that 1MIL is 3.6 inches at 100yds that means at 25yds 1MIL would be 1/4 of 3.6 inches or .9 inches. To move the point of impact 1.50 inches up, doing the math says I would need to holdover about 1.7 MILS which would mathematically be 1.53 inches which is as close as I can get to 1.50 inches. However, It takes a holdover of exactly 2.0MILS to hit dead center at 25yds. We all know that 2.0 MILS at 25yds is exactly 1.8 inches which is 0.3 inches more than 1.50 inches. What is going on here?????
Here is the 100yd target with red bullseye and the 25yd target showing point of impact of crosshairs and 2.0MILS holdover.
My question to the cognoscenti is WTF????

 

[Rob01]

Why do you care how many inches it is? Your scope is in mils. Measure with the reticle and dial or hold the difference. Simple.

 

[stanley_white]

Why do you care how many inches it is? Your scope is in mils. Measure with the reticle and dial or hold the difference. Simple.

This and I will add to the OP — beware of counterproductive curiosity.

-Stan

 

[lash]

My Browning X-Bolt Max Varmint/Target is zeroed at 100yds. To hit zero at 25yds I want to holdover because I want to retain the 100yd zero for shooting 625yds at Pala shooting range. Upon firing the rifle at 25yds indoors the point of impact is 1.50 inches low as measured by calipers. So knowing that 1MIL is 3.6 inches at 100yds that means at 25yds 1MIL would be 1/4 of 3.6 inches or .9 inches. To move the point of impact 1.50 inches up, doing the math says I would need to holdover about 1.7 MILS which would mathematically be 1.53 inches which is as close as I can get to 1.50 inches. However, It takes a holdover of exactly 2.0MILS to hit dead center at 25yds. We all know that 2.0 MILS at 25yds is exactly 1.8 inches which is 0.3 inches more than 1.50 inches. What is going on here?????
Here is the 100yd target with red bullseye and the 25yd target showing point of impact of crosshairs and 2.0MILS holdover.
My question to the cognoscenti is WTF????

Ballistic arcs are not linear. Period.

Go spend a minute to lookup a graph of a ballistic curve. Then you will understand better than we can tell you. Specifically a ballistic representation of the curve with 100yd zero.

 

[Holliday]

Do.

Not.

Convert.

 

[TonyAngel]

Well, 1 mil at 100 is about 3.36". 2 mils at 100 is roughly 7". So, 2 mils at 50 is roughly 3.5" and at 25, roughly 1.75"; so, yeah, sounds about right to me.

And heed the words from the wise. Don't try to convert. You paid for the reticle. Trust it.