Metric trajectory correction formula

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I hear they cut pies into slices across the pond too. 🤣🤣🤣
Think of a radian as the angle of a pizza slice where the straight sides are as long as the curved side.
1740153275706.png

The entire pizza has a radius r, which is also the length of the straight sides of each slice
The circumference of that pizza is 2*pi*r

If we now divide the 360 degrees of the pizza by 2*pi, then we get the approximate degree value of 57.3 degrees per radian.
By using 2*pi as the divider for the arc, we avoid a conversion constant between angle and arc length.

The beauty of the SI system is not only that each unit itself is on a decimal scale (rather than 12 inch in 1 foot, 5280 feet in a mile, etc.) but more importantly that the different units correlate in a physically meaningful way.
You'll appreciate this once you have to deal with electrical charges, viscosity, magnetism, etc. where the Imperial system becomes an insane mess.
 
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Think of a radian as the angle of a pizza slice where the straight sides are as long as the curved side.
View attachment 8623152
The entire pizza has a radius r, which is also the length of the straight sides of each slice
The circumference of that pizza is 2*pi*r

If we now divide the 360 degrees of the pizza by 2*pi, then we get the approximate degree value of 57.3 degrees per radian.
By using 2*pi as the divider for the arc, we avoid a conversion constant between angle and arc length.

The beauty of the SI system is not only that each unit itself is on a decimal scale (rather than 12 inch in 1 foot, 5280 feet in a mile, etc.) but more importantly that the different units correlate in a physically meaningful way.
You'll appreciate this once you have to deal with electrical charges, viscosity, magnetism, etc. where the Imperial system becomes an insane mess.
Yeah but it's MY insane mess.
 
Metric conversion:
2.54 cm = 1 inch (exactly--its actually the definition of the inch)
2 * Pi * 1000 milliradians = 360 degrees = 1 circle.

Because angles are ratios, they have no dimensions of length, they are independent of the measuring system.

arc length (vertical distance) is expressed as angle x radius (of the circle containing the arc, aka "distance to target"). There are pi/180 radians per degree.

So if you want measurements from degrees (MOA) its just (pi/180)*distance. If you want meters , plug in the distance in meters, yards, plus in the distance in yards.

If you want measurements from radians (MIL) its just angle*distance. Again, plug in the distance in your units.

THis assumes you can convert from milliradians to radians and cm to m and inches to feet (which is actually like super hard man)

ANd you bitches made fun of me for paying attention in math.

And for the astute among you yes, the arc length is not the same as the vertical distance. But its like super super close (I think at 100y the difference is in the 4th decimal point).
 
And for the astute among you yes, the arc length is not the same as the vertical distance. But its like super super close (I think at 100y the difference is in the 4th decimal point).
Sort of, kinda. But it’s more like, as the angle increases then the difference becomes greater.
Regardless if it’s an inch or a mile. Ratios.

I think @Aftermath could word it better than me.


But in rifle scopes it doesn't matter at all. So effectively, you are correct.
 
Metric conversion:
2.54 cm = 1 inch (exactly--its actually the definition of the inch)
2 * Pi * 1000 milliradians = 360 degrees = 1 circle.

Because angles are ratios, they have no dimensions of length, they are independent of the measuring system.

arc length (vertical distance) is expressed as angle x radius (of the circle containing the arc, aka "distance to target"). There are pi/180 radians per degree.

So if you want measurements from degrees (MOA) its just (pi/180)*distance. If you want meters , plug in the distance in meters, yards, plus in the distance in yards.

If you want measurements from radians (MIL) its just angle*distance. Again, plug in the distance in your units.

THis assumes you can convert from milliradians to radians and cm to m and inches to feet (which is actually like super hard man)

ANd you bitches made fun of me for paying attention in math.

And for the astute among you yes, the arc length is not the same as the vertical distance. But its like super super close (I think at 100y the difference is in the 4th decimal point).
1740167038582.gif
 
Sort of, kinda. But it’s more like, as the angle increases then the difference becomes greater.
Regardless if it’s an inch or a mile. Ratios.

I think @Aftermath could word it better than me.


But in rifle scopes it doesn't matter at all. So effectively, you are correct.
The error in % is indeed independent of distance.
Here are the numbers:
1740170212422.png
1740170473948.png
 
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Sort of, kinda. But it’s more like, as the angle increases then the difference becomes greater.
Regardless if it’s an inch or a mile. Ratios.

I think @Aftermath could word it better than me.


But in rifle scopes it doesn't matter at all. So effectively, you are correct.
You're right. Even head maff monkey makes a mistatement now and then.

the "true" distance is sin (angle) * distance. (BC in Alpine's Pic). (or DE--more on that in a minute)
Arc length is BE.

at small angles, sin (angle) is basically the angle itself and our scope measurements fit really really well into that approximation. (you can use tangent, its just a slightly different approx, but the reason to use sin is it makes the math easy

The forumula for sine is x - x^3/3! + x^5/5! so if x is small, its basically "x"

(and for the additionally pendatic among you for small x, cos x = 1 and tan = sin/cos or x/1 so you can see its pretty consistent around here whether you use sin or tan).

cos = 1 -x^2/2+x^4/4!

and for double double pendatic bonus points DE>BC because cosine < 1 when cosine is non-zero. So you can see whether you take BC or BD its really just a matter of which approximation you want to deal with.
 
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I am trying to find a trajectory correction formula for metric units and mrad. I have no problem finding a mrad formula where it butchers mrads with inches and yards.

Mrads and centimetres and meters
I'll make it simple for you.

.1 Mil at 100 yards is .36-inches and .36-inches is 9.14-mm. You can take it from there using and excel spreadsheet .....
 
Sort of, kinda. But it’s more like, as the angle increases then the difference becomes greater.
Regardless if it’s an inch or a mile. Ratios.
Correct.

You are much better at math than you give yourself credit for.

Those small town Idaho schools [where we all knew (and mostly still know) that school is your one chance to learn some stuff for free...no blood loss, no lost wages, no pushups...so you apply yourself] (or get your ass beat by mom and dad) do a real great job. In a couple more years you will be driving a truck, cutting trees, driving rail spikes, mixing chemicals to make paper or filling trays of primer cups with a volatile compound...just so you can buy a 6 pack of beer and a steak or some diapers and Gerber green beans.
 
The error in % is indeed independent of distance.
Here are the numbers:
View attachment 8623353 View attachment 8623354
That pretty chart shows 1-200 mil. That's misleading to me. I'm not using artillery, I'm using a rifle inside 1000 meters.

That equates to 0 Mil (actual) at 100 meters (E) and 9 Mil (actual) at 1000 (D). That's the reason we use .1 Mil. Sooo, The relevant range is inside your first two rows and so are the angles (1/2 degree elevation). I can't close my eyes and move the rifle up 1/2 degree and nail it.
 
Same shit but with fractions. I like tenths (.1 Mil) - lot easier to work in my head. And the difference between Mil and MOA in scope clicks is smaller than the margin of error between the two measurements - 0.09825 inch. 4-scope clicks per MOA (1/4 MOA clicks) vs 10-scope clicks per Mil (.1 Mil)

All you need to know shooting Mil is one number .36. That is .36-inches per click at 100. The rest is sooo easy. Unless you cant remember one number :ROFLMAO:.
 
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That pretty chart shows 1-200 mil. That's misleading to me. I'm not using artillery, I'm using a rifle inside 1000 meters.

That equates to 0 Mil (actual) at 100 meters (E) and 9 Mil (actual) at 1000 (D). That's the reason we use .1 Mil. Sooo, The relevant range is inside your first two rows and so are the angles (1/2 degree elevation). I can't close my eyes and move the rifle up 1/2 degree and nail it.
I purposely took this to the extreme to show what DocRDS said :"And for the astute among you yes, the arc length is not the same as the vertical distance. But its like super super close (I think at 100y the difference is in the 4th decimal point)."

In other words, for typical rifle applications you can save yourself the effort of using trigonometric functions and just go with the arc length, which is simple multiplication of mils times distance as shown in previous posts.

OTOH, artillery folks HAVE to get a little fancier with the math.
 
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I purposely took this to the extreme to show what DocRDS said And for the astute among you yes, the arc length is not the same as the vertical distance. But its like super super close (I think at 100y the difference is in the 4th decimal point)."

In other words, for typical rifle applications you can save yourself the effort of using trigonometric functions and just go with the arc length, which is simple multiplication of mils times distance as shown in previous posts.

OTOH, artillery folks HAVE to get a little fancier with the math.
Lest we forget the Gremlins. The Gremlin leading the pack is called Dispersion. and there are many others whose purpose in life is to work feverishly on ruining your shot! Understanding math and geometry is very helpful, until the Gremlins show up, which they always do :eek: .