Just saw a mention that some new gun shown at this year's SHOT Show comes with a 3-inch twist rifled barrel. Some barrel makers have made those kind of twist-rates for ballistic test barrels used for short-range, reduced velocity testing of subsonic bullet behavior or extreme range terminal ballistics. Some riflemen think fast twist barrels cause a problem with excess chamber pressures. Super fast-twist barrels DO cause some increase in inertial resistance during firing, but not nearly as much as most riflemen seem to imagine. Engraving and barrel friction forces are not increased with faster twist rifling, all else being equal. The formulation for the extra inertial resistance in accelerating the engraved bullet with faster rifling twist-rates is a bit tricky, but I thought about it awhile and believe I have it correct.
EDIT: I found the expression for friction-free torque versus clamping force for machine screw threads in Shigley's Mechanical Engineering Design (4th Ed.), page 365, equation (h), where the rifling twist (n*d) is substituted for thread pitch (1/TPI, for example). I have corrected my formulation accordingly.
With linear acceleration (A), the resistive force (F) is given by bullet mass (m) multiplied by that acceleration (A). Adding the "spin-up" torque due to rifling twist can be formulated as effectively equivalent to increasing the bullet mass (m) by a small fraction. That small fraction is 0.0113 (or 1.13-percent increase) for my 265-gr copper ULD bullet fired from a 6.6-inch twist 338-caliber barrel made by Bartlein. That is for a twist-rate of 20 calibers per turn, which is very quick twist. [I use the bore diameter 0.330-inch as 1.00 calibers.] That is to say, firing this 265-gr copper ULD bullet through a 6.6-inch twist barrel will produce the same pressure profile as firing a copper bullet weighing 268 grains from a hypothetical zero-twist rifled barrel.
If you want to find this fractional effective bullet mass (or weight) increase (f) for your rifled barrels, here is the formulation:
f = [(2 Pi/n)*(kx/d)]^2
where n = number of calibers (d) per turn for your rifling and kx is the Radius of Gyration of the mass distribution of your rifle bullet about its spin-axis (x). Any monolithic ULD or VLD rifle bullet will have kx/d (0<kx/d<0.5) very near to the 0.338 of my bullet designs. [I will happily share my development of this formulation with any who care for it.]
For a more typical twist-rate of n = 40 calibers per turn, say a 30-caliber barrel with a 12-inch twist-rate, the effective bullet weight increase would be just one quarter as much (0.00282), and so forth. About this much effective bullet weight increase (0.75 grains here) is already factored into QuickLOAD(c) interior ballistics calculations because they do not even ask for input of rifling twist-rate, apparently assuming it will be in this "normal" range. So, one could argue for reducing the formulation shown above by an additional factor of 0.75.
I don't buy any argument for selecting a gain-twist barrel to prevent early rise in chamber pressures. The pressure difference is too small to risk twisting your rifling engraved bullets as they traverse the bore of any gain-twist barrel.
EDIT: I found the expression for friction-free torque versus clamping force for machine screw threads in Shigley's Mechanical Engineering Design (4th Ed.), page 365, equation (h), where the rifling twist (n*d) is substituted for thread pitch (1/TPI, for example). I have corrected my formulation accordingly.
With linear acceleration (A), the resistive force (F) is given by bullet mass (m) multiplied by that acceleration (A). Adding the "spin-up" torque due to rifling twist can be formulated as effectively equivalent to increasing the bullet mass (m) by a small fraction. That small fraction is 0.0113 (or 1.13-percent increase) for my 265-gr copper ULD bullet fired from a 6.6-inch twist 338-caliber barrel made by Bartlein. That is for a twist-rate of 20 calibers per turn, which is very quick twist. [I use the bore diameter 0.330-inch as 1.00 calibers.] That is to say, firing this 265-gr copper ULD bullet through a 6.6-inch twist barrel will produce the same pressure profile as firing a copper bullet weighing 268 grains from a hypothetical zero-twist rifled barrel.
If you want to find this fractional effective bullet mass (or weight) increase (f) for your rifled barrels, here is the formulation:
f = [(2 Pi/n)*(kx/d)]^2
where n = number of calibers (d) per turn for your rifling and kx is the Radius of Gyration of the mass distribution of your rifle bullet about its spin-axis (x). Any monolithic ULD or VLD rifle bullet will have kx/d (0<kx/d<0.5) very near to the 0.338 of my bullet designs. [I will happily share my development of this formulation with any who care for it.]
For a more typical twist-rate of n = 40 calibers per turn, say a 30-caliber barrel with a 12-inch twist-rate, the effective bullet weight increase would be just one quarter as much (0.00282), and so forth. About this much effective bullet weight increase (0.75 grains here) is already factored into QuickLOAD(c) interior ballistics calculations because they do not even ask for input of rifling twist-rate, apparently assuming it will be in this "normal" range. So, one could argue for reducing the formulation shown above by an additional factor of 0.75.
I don't buy any argument for selecting a gain-twist barrel to prevent early rise in chamber pressures. The pressure difference is too small to risk twisting your rifling engraved bullets as they traverse the bore of any gain-twist barrel.
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