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Fieldcraft Understanding MOA
- Thread starter coues7
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Re: Understanding MOA
Lets put an example to this in MRADS for my weapon so I can jump on board and get some knowledge as well. S&B 4-16x50 PMII LP with 1 click= 1cm. (Gun zeroed at 200 yards)
I have a target at 400 yards my table tells me I will be 21.6 inches Low at that range. Where do I go from here? How many clicks? How would it be listed? If my scope would be in MOA it wouldn't be a problem. However this whole MRAD thing is killing me.
Lets put an example to this in MRADS for my weapon so I can jump on board and get some knowledge as well. S&B 4-16x50 PMII LP with 1 click= 1cm. (Gun zeroed at 200 yards)
I have a target at 400 yards my table tells me I will be 21.6 inches Low at that range. Where do I go from here? How many clicks? How would it be listed? If my scope would be in MOA it wouldn't be a problem. However this whole MRAD thing is killing me.
Re: Understanding MOA
There is no reason to zero at 200 yards, unless you can't <span style="font-style: italic">get</span> the scope to zero at 100 yards. You're just creating confusion for yourself with a non-100-yard zero.
However, in the example you posted, at 400 yards, each 0.1 milliradian click is 4 * 0.36 inches = 1.44 inches. So you need to come up 21.6/1.44 = 15 clicks or 1.5 mils.
However, stop thinking in clicks. Re-zero your scope at 100 yards, and start acquiring dope out to however far you want to shoot. Log the scope setting in mils, and learn your dope in mils.
When you're adjusting the scope, put the elevation setting on in mils, not clicks.
There is no reason to zero at 200 yards, unless you can't <span style="font-style: italic">get</span> the scope to zero at 100 yards. You're just creating confusion for yourself with a non-100-yard zero.
However, in the example you posted, at 400 yards, each 0.1 milliradian click is 4 * 0.36 inches = 1.44 inches. So you need to come up 21.6/1.44 = 15 clicks or 1.5 mils.
However, stop thinking in clicks. Re-zero your scope at 100 yards, and start acquiring dope out to however far you want to shoot. Log the scope setting in mils, and learn your dope in mils.
When you're adjusting the scope, put the elevation setting on in mils, not clicks.
Re: Understanding MOA
Now that is something I can get my mind around. That is all I needed. I will re-zero the gun in at 100 yards.
Lindy, thanks again for making the difficult simple having it explained using my own example made things "Click", no pun intended!
Thanks again,
T. Defense
Now that is something I can get my mind around. That is all I needed. I will re-zero the gun in at 100 yards.
Lindy, thanks again for making the difficult simple having it explained using my own example made things "Click", no pun intended!
Thanks again,
T. Defense
Re: Understanding MOA
So, I'm still not clear on weather the Leupold with CM dials are .1 mil or .1 cm. Any help on this would be helpful. Thanks
So, I'm still not clear on weather the Leupold with CM dials are .1 mil or .1 cm. Any help on this would be helpful. Thanks
Re: Understanding MOA
Scopes adjust by changing the angle between the line of sight and the line of the bore.
A centimeter is not a unit of angular measurement.
Scopes typically adjust in MOA, Inches per Hundred Yards (IPHY), or milliradians, usually fractions of those angular measurements.
So far as I know, the only Leupold scope currently in production adjusts in 0.05 milliradian clicks. Leupold is said to have promised 0.1 mil clicks <span style="font-style: italic">real soon now</span>.
Scopes adjust by changing the angle between the line of sight and the line of the bore.
A centimeter is not a unit of angular measurement.
Scopes typically adjust in MOA, Inches per Hundred Yards (IPHY), or milliradians, usually fractions of those angular measurements.
So far as I know, the only Leupold scope currently in production adjusts in 0.05 milliradian clicks. Leupold is said to have promised 0.1 mil clicks <span style="font-style: italic">real soon now</span>.
Re: Understanding MOA
Ok thanks I was a little confused about the way I saw the leupold advertised.
Ok thanks I was a little confused about the way I saw the leupold advertised.
Re: Understanding MOA
Excellent read! I even made copies to study during my travels next week. Thanks to all,I learned a lot and relearned even more from years of not using.
Excellent read! I even made copies to study during my travels next week. Thanks to all,I learned a lot and relearned even more from years of not using.
Re: Understanding MOA
can some 1 help me. i know a little aboutmoa and how to dope for example 10 or 11 or 12moa eg, all good.. where i get stuck is when the numbers get bigger like 22.8 wat is the walue of .8 cliks,, can some 1 help me any info would be grate.thanks
can some 1 help me. i know a little aboutmoa and how to dope for example 10 or 11 or 12moa eg, all good.. where i get stuck is when the numbers get bigger like 22.8 wat is the walue of .8 cliks,, can some 1 help me any info would be grate.thanks
Re: Understanding MOA
Hey guys. Im new with all this but have read all the info on the FAQ. Some of it was difficult to understand due to all the extra chatter and I couldnt find a solid example. So I would like to put a thought out and would really appreciate if someone could point out my errors or could lead me right.
The numbers Im going to use are made up. Scope is measured 1/4MOA @ 100yd. Here we go.
Find my distance to target with the formula for MOA. H"x100/MOA=X Say x is 500. 5 x 1.047 = 5.235". Then I take that number and multiply it by the inches of drop according to the ballistics on the round Im using. So now that I got a total of say 14.434" how do I put that into my elevation turret? The number of 1/4MOA it takes to reach 14.434? 14.5 x 4? 1/4MOA 58 clicks on the turret?
Or do you add 1/4MOA for each 100yd? So 200yd would be 1/2MOA, 300yd would be 3/4MOA, etc. for every click of the turret? This would make 500yd 1.25MOA for every "click" of the turret at 500yd?
Am I following everyone correctly? Or did I get lost interpreting the lingo?
Hey guys. Im new with all this but have read all the info on the FAQ. Some of it was difficult to understand due to all the extra chatter and I couldnt find a solid example. So I would like to put a thought out and would really appreciate if someone could point out my errors or could lead me right.
The numbers Im going to use are made up. Scope is measured 1/4MOA @ 100yd. Here we go.
Find my distance to target with the formula for MOA. H"x100/MOA=X Say x is 500. 5 x 1.047 = 5.235". Then I take that number and multiply it by the inches of drop according to the ballistics on the round Im using. So now that I got a total of say 14.434" how do I put that into my elevation turret? The number of 1/4MOA it takes to reach 14.434? 14.5 x 4? 1/4MOA 58 clicks on the turret?
Or do you add 1/4MOA for each 100yd? So 200yd would be 1/2MOA, 300yd would be 3/4MOA, etc. for every click of the turret? This would make 500yd 1.25MOA for every "click" of the turret at 500yd?
Am I following everyone correctly? Or did I get lost interpreting the lingo?
Re: Understanding MOA
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: DEATHONCALL</div><div class="ubbcode-body">Hey guys. Im new with all this but have read all the info on the FAQ. Some of it was difficult to understand due to all the extra chatter and I couldnt find a solid example. So I would like to put a thought out and would really appreciate if someone could point out my errors or could lead me right.
The numbers Im going to use are made up. Scope is measured 1/4MOA @ 100yd. Here we go.
Find my distance to target with the formula for MOA. H"x100/MOA=X Say x is 500. 5 x 1.047 = 5.235". Then I take that number and multiply it by the inches of drop according to the ballistics on the round Im using. So now that I got a total of say 14.434" how do I put that into my elevation turret? The number of 1/4MOA it takes to reach 14.434? 14.5 x 4? 1/4MOA 58 clicks on the turret?
Or do you add 1/4MOA for each 100yd? So 200yd would be 1/2MOA, 300yd would be 3/4MOA, etc. for every click of the turret? This would make 500yd 1.25MOA for every "click" of the turret at 500yd?
Am I following everyone correctly? Or did I get lost interpreting the lingo? </div></div>
Stop thinking in clicks and think in MOA or Mil. For example, if your drop in inches at 500 yards is 50" that subtends approximately 9.6 MOA (9.6 x 1.047MOA = 10" at 100 yards, which translates to 50" at 500 yards). You'd then make the necessary number of clicks to reach 9.6 MOA (if your scope adjusts in .25 or .5 MOA per click, the closest you'll get is 9.5 MOA).
Does this make sense?
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: DEATHONCALL</div><div class="ubbcode-body">Hey guys. Im new with all this but have read all the info on the FAQ. Some of it was difficult to understand due to all the extra chatter and I couldnt find a solid example. So I would like to put a thought out and would really appreciate if someone could point out my errors or could lead me right.
The numbers Im going to use are made up. Scope is measured 1/4MOA @ 100yd. Here we go.
Find my distance to target with the formula for MOA. H"x100/MOA=X Say x is 500. 5 x 1.047 = 5.235". Then I take that number and multiply it by the inches of drop according to the ballistics on the round Im using. So now that I got a total of say 14.434" how do I put that into my elevation turret? The number of 1/4MOA it takes to reach 14.434? 14.5 x 4? 1/4MOA 58 clicks on the turret?
Or do you add 1/4MOA for each 100yd? So 200yd would be 1/2MOA, 300yd would be 3/4MOA, etc. for every click of the turret? This would make 500yd 1.25MOA for every "click" of the turret at 500yd?
Am I following everyone correctly? Or did I get lost interpreting the lingo? </div></div>
Stop thinking in clicks and think in MOA or Mil. For example, if your drop in inches at 500 yards is 50" that subtends approximately 9.6 MOA (9.6 x 1.047MOA = 10" at 100 yards, which translates to 50" at 500 yards). You'd then make the necessary number of clicks to reach 9.6 MOA (if your scope adjusts in .25 or .5 MOA per click, the closest you'll get is 9.5 MOA).
Does this make sense?
Re: Understanding MOA
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: DEATHONCALL</div><div class="ubbcode-body">H
Or do you add 1/4MOA for each 100yd? So 200yd would be 1/2MOA, 300yd would be 3/4MOA, etc. for every click of the turret? This would make 500yd 1.25MOA for every "click" of the turret at 500yd?
Am I following everyone correctly? Or did I get lost interpreting the lingo?</div></div>
yes, 1/4 at 100 is 1 1/4 at 500. since you know your drop, you dial that into scope knowing each click value at that range.
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: DEATHONCALL</div><div class="ubbcode-body">H
Or do you add 1/4MOA for each 100yd? So 200yd would be 1/2MOA, 300yd would be 3/4MOA, etc. for every click of the turret? This would make 500yd 1.25MOA for every "click" of the turret at 500yd?
Am I following everyone correctly? Or did I get lost interpreting the lingo?</div></div>
yes, 1/4 at 100 is 1 1/4 at 500. since you know your drop, you dial that into scope knowing each click value at that range.
Re: Understanding MOA
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: usmc02xx</div><div class="ubbcode-body"><div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: DEATHONCALL</div><div class="ubbcode-body">do you add 1/4MOA for each 100yd? So 200yd would be 1/2MOA, 300yd would be 3/4MOA, etc. for every click of the turret? This would make 500yd 1.25MOA for every "click" of the turret at 500yd? </div></div> yes, 1/4 at 100 is 1 1/4 at 500. since you know your drop, you dial that into scope knowing each click value at that range. </div></div> WTF? Are you guys simply making this up?
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: usmc02xx</div><div class="ubbcode-body"><div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: DEATHONCALL</div><div class="ubbcode-body">do you add 1/4MOA for each 100yd? So 200yd would be 1/2MOA, 300yd would be 3/4MOA, etc. for every click of the turret? This would make 500yd 1.25MOA for every "click" of the turret at 500yd? </div></div> yes, 1/4 at 100 is 1 1/4 at 500. since you know your drop, you dial that into scope knowing each click value at that range. </div></div> WTF? Are you guys simply making this up?
Re: Understanding MOA
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Graham</div><div class="ubbcode-body"><div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: usmc02xx</div><div class="ubbcode-body"><div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: DEATHONCALL</div><div class="ubbcode-body">do you add 1/4MOA for each 100yd? So 200yd would be 1/2MOA, 300yd would be 3/4MOA, etc. for every click of the turret? This would make 500yd 1.25MOA for every "click" of the turret at 500yd? </div></div> yes, 1/4 at 100 is 1 1/4 at 500. since you know your drop, you dial that into scope knowing each click value at that range. </div></div> WTF? Are you guys simply making this up?</div></div>
edit because i mis-spoke, and told graham to stfu. eating crow.
OP. i stand by my statement. But i can see the confusion. I'm relating one moa to one inch (trying to keep the tough math out and replicating you original statement), not minute of angle. So saying that.. ROUGHLY SPEAKING if it moved me 1/4 inch at 100 then it will be 1/2 inch at 200. and so on. in 1/4 inch values then 500 would be 1 and 1/4 inches per click. If i must adjust 50 inches to compensate drop then i can divide that by 1.25. That's 40 clicks.
your particular example..
<span style="font-weight: bold">For example in exbal @ 500 yards with (1/4" MOA clicks) it tells me 11 MOA with -57" of drop. How many clicks or turns do I need</span>
<span style="font-weight: bold">Roughly</span> 46 clicks. if your turrets are marked as 1 moa every 4 clicks then 10 marks and 3 clicks. So the 11 was pretty much dead on.
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Graham</div><div class="ubbcode-body"><div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: usmc02xx</div><div class="ubbcode-body"><div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: DEATHONCALL</div><div class="ubbcode-body">do you add 1/4MOA for each 100yd? So 200yd would be 1/2MOA, 300yd would be 3/4MOA, etc. for every click of the turret? This would make 500yd 1.25MOA for every "click" of the turret at 500yd? </div></div> yes, 1/4 at 100 is 1 1/4 at 500. since you know your drop, you dial that into scope knowing each click value at that range. </div></div> WTF? Are you guys simply making this up?</div></div>
edit because i mis-spoke, and told graham to stfu. eating crow.
OP. i stand by my statement. But i can see the confusion. I'm relating one moa to one inch (trying to keep the tough math out and replicating you original statement), not minute of angle. So saying that.. ROUGHLY SPEAKING if it moved me 1/4 inch at 100 then it will be 1/2 inch at 200. and so on. in 1/4 inch values then 500 would be 1 and 1/4 inches per click. If i must adjust 50 inches to compensate drop then i can divide that by 1.25. That's 40 clicks.
your particular example..
<span style="font-weight: bold">For example in exbal @ 500 yards with (1/4" MOA clicks) it tells me 11 MOA with -57" of drop. How many clicks or turns do I need</span>
<span style="font-weight: bold">Roughly</span> 46 clicks. if your turrets are marked as 1 moa every 4 clicks then 10 marks and 3 clicks. So the 11 was pretty much dead on.
Re: Understanding MOA
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: DFOOSKING</div><div class="ubbcode-body">Beginners get all wrapped up in the math aspect of it IMO. They're so scared that they can't handle it that they hang on every little piece of is as if were the greatest book ever written.
And although the definition is important...its the word that we use day to day. I can't remember the last time the number 1.047 came up during a shooting session. But I've said "1 minute low or right" or "2 mils low".
That's why I posted pics...because once you see what it is your applying it gets easier. The definition is simply not enough for some people.
I have a HS education in math that reaches competently Algebra I....
this stuff isnt that hard to do but it is hard to convey with a definition alone to some shooters.
Its like teaching the makeup of a car motor's piston ring...when driving is the goal. Is it important to know that minute detail....sure...but your not focusing on it day to day.
</div></div>
I wasnt wrapped in the math. I just to know what my MOA change was at 500 vs 100yd if any (Still not sure what that is called). I figured out for myself the value changes but need a confirm. I guess I didnt know how to word it. I did want to know all the math since I dont own a smart phone with a fancy calculator and I dont have anywhere to shoot past 100yd. All I have acess to is pen, paper and internet once a week or so.
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: DFOOSKING</div><div class="ubbcode-body">Beginners get all wrapped up in the math aspect of it IMO. They're so scared that they can't handle it that they hang on every little piece of is as if were the greatest book ever written.
And although the definition is important...its the word that we use day to day. I can't remember the last time the number 1.047 came up during a shooting session. But I've said "1 minute low or right" or "2 mils low".
That's why I posted pics...because once you see what it is your applying it gets easier. The definition is simply not enough for some people.
I have a HS education in math that reaches competently Algebra I....
this stuff isnt that hard to do but it is hard to convey with a definition alone to some shooters.
Its like teaching the makeup of a car motor's piston ring...when driving is the goal. Is it important to know that minute detail....sure...but your not focusing on it day to day.
</div></div>
I wasnt wrapped in the math. I just to know what my MOA change was at 500 vs 100yd if any (Still not sure what that is called). I figured out for myself the value changes but need a confirm. I guess I didnt know how to word it. I did want to know all the math since I dont own a smart phone with a fancy calculator and I dont have anywhere to shoot past 100yd. All I have acess to is pen, paper and internet once a week or so.
Re: Understanding MOA
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: usmc02xx</div><div class="ubbcode-body"><div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Graham</div><div class="ubbcode-body"><div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: usmc02xx</div><div class="ubbcode-body"><div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: DEATHONCALL</div><div class="ubbcode-body">do you add 1/4MOA for each 100yd? So 200yd would be 1/2MOA, 300yd would be 3/4MOA, etc. for every click of the turret? This would make 500yd 1.25MOA for every "click" of the turret at 500yd? </div></div> yes, 1/4 at 100 is 1 1/4 at 500. since you know your drop, you dial that into scope knowing each click value at that range. </div></div> WTF? Are you guys simply making this up?</div></div>
edit because i mis-spoke, and told graham to stfu. eating crow.
OP. i stand by my statement. But i can see the confusion. I'm relating one moa to one inch (trying to keep the tough math out and replicating you original statement), not minute of angle. So saying that.. ROUGHLY SPEAKING if it moved me 1/4 inch at 100 then it will be 1/2 inch at 200. and so on. in 1/4 inch values then 500 would be 1 and 1/4 inches per click. If i must adjust 50 inches to compensate drop then i can divide that by 1.25. That's 40 clicks.
your particular example..
<span style="font-weight: bold">For example in exbal @ 500 yards with (1/4" MOA clicks) it tells me 11 MOA with -57" of drop. How many clicks or turns do I need</span>
<span style="font-weight: bold">Roughly</span> 46 clicks. if your turrets are marked as 1 moa every 4 clicks then 10 marks and 3 clicks. So the 11 was pretty much dead on. </div></div>
Ok, thats why I couldnt word my question right. Where does the 11MOA come from? The " of drop came from the caliber at that yardage correct?
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: usmc02xx</div><div class="ubbcode-body"><div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Graham</div><div class="ubbcode-body"><div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: usmc02xx</div><div class="ubbcode-body"><div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: DEATHONCALL</div><div class="ubbcode-body">do you add 1/4MOA for each 100yd? So 200yd would be 1/2MOA, 300yd would be 3/4MOA, etc. for every click of the turret? This would make 500yd 1.25MOA for every "click" of the turret at 500yd? </div></div> yes, 1/4 at 100 is 1 1/4 at 500. since you know your drop, you dial that into scope knowing each click value at that range. </div></div> WTF? Are you guys simply making this up?</div></div>
edit because i mis-spoke, and told graham to stfu. eating crow.
OP. i stand by my statement. But i can see the confusion. I'm relating one moa to one inch (trying to keep the tough math out and replicating you original statement), not minute of angle. So saying that.. ROUGHLY SPEAKING if it moved me 1/4 inch at 100 then it will be 1/2 inch at 200. and so on. in 1/4 inch values then 500 would be 1 and 1/4 inches per click. If i must adjust 50 inches to compensate drop then i can divide that by 1.25. That's 40 clicks.
your particular example..
<span style="font-weight: bold">For example in exbal @ 500 yards with (1/4" MOA clicks) it tells me 11 MOA with -57" of drop. How many clicks or turns do I need</span>
<span style="font-weight: bold">Roughly</span> 46 clicks. if your turrets are marked as 1 moa every 4 clicks then 10 marks and 3 clicks. So the 11 was pretty much dead on. </div></div>
Ok, thats why I couldnt word my question right. Where does the 11MOA come from? The " of drop came from the caliber at that yardage correct?
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