I was wondering if any of you are accounting for differences in station pressure when firing ELR @ high angles. I watched a vid here some time ago on a guy (sorry, don't remember who) who was shooting @ a mile up hill, & adjusted his station pressure down for the thinner air high up near the target. I gave this a try @ the recent ELR match we had in my AO by fundamentally guessing the pressure drop for my guessed altitude change to the target. I ended up getting it right with a 1st rnd hit @ 1645 yds with a 18* angle up to the target. Now I just found a free app called triangle solver where you can enter the angle on one side with the distance, & the solver will give you the rest of the angles, & distances. Using this I entered the distance to target (1645) with the degrees (18) for one side of the triangle, & it gave me 508yds as the height to the target, which is 1525 ft. Using the rule of thumb of 1"hg/1000' elevation, & 3.5*F drop in temp/1000' elevation (using the DA model temp change) I can estimate the average air density for the shot. So in other words the pressure where I was is 27.8"hg, & the calculated pressure @ the target should be 26.2"hg with a difference of 5*F overall. These differences amount to almost 2moa in flight path.
What are your thoughts?
What are your thoughts?
