Re: Spindrift Calculation??
<div class="ubbcode-block"><div class="ubbcode-header">Originally Posted By: Gunfighter14e2</div><div class="ubbcode-body">
Math will always render the correct answer, assumeing correct input. I'm not sure where the end if this debate is, but I know something is happening other than wind down range, and the sd cant I use seems to work for me.
If everyone read/ranged everything the same, no one would never miss. All the programs seem to arrive at about the same answers only after the same field data is inputed. </div></div>
I know this is completely beating a dead horse, but I think you are getting closer to seeing things a little differently, but since we're here, I'll simplify the math a bit.
1 MOA @ 1000 yards is 10 inches
Doppler says 175gr bullet has 11.43" of Spin Drift @ 1000 yards, which is now being read as a verifable number by some... in fact an "ah ha" moment in this discussion.
So, in no wind situation a center hold on an 18" wide plate means only one thing -- the shooter misses the plate each and every time by 1 MOA or in the case of doppler 2.43" to the right.
Now, add that to each and every wind call and automatically the shooter misses the plate by the same numbers, there is no way to use any wind table to any effect without the addition of pure luck because the shooter will always have to be either 2.43" short or long on their call, period. Cause without that additional correction to center you still miss the plate.
The math gets no simpler than that, unless there is something else affected by select shooters to influence this number, which in my contention is trigger control or some element of the fundamentals of marksmanship, which I say is more common and greater a factor.
So to say say spin drift effects every 308 rifle by 1 MOA or more is either wrong, or more so, X number of shooters pull their shots right more than Y accounting for the math not working out. In which case, X adds in spin drift rather than dialing for "their" trigger or flinch.
Is it the gun, or the shooter ? cause if its the gun, my math is undeniable.
there is no way to hit the target without the correction wind or not.
Now, finally so there is no misunderstanding me, I contend SD is equal to .5 MOA or less depending on the rifle, but in essence half of the noted number at 1000 yards with a 308. Other bullets and calibers have other numbers and no two rifles are exactly the same.
